25x^2-10x+28=0

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Solution for 25x^2-10x+28=0 equation:


Simplifying
25x2 + -10x + 28 = 0

Reorder the terms:
28 + -10x + 25x2 = 0

Solving
28 + -10x + 25x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
25 the coefficient of the squared term: 

Divide each side by '25'.
1.12 + -0.4x + x2 = 0

Move the constant term to the right:

Add '-1.12' to each side of the equation.
1.12 + -0.4x + -1.12 + x2 = 0 + -1.12

Reorder the terms:
1.12 + -1.12 + -0.4x + x2 = 0 + -1.12

Combine like terms: 1.12 + -1.12 = 0.00
0.00 + -0.4x + x2 = 0 + -1.12
-0.4x + x2 = 0 + -1.12

Combine like terms: 0 + -1.12 = -1.12
-0.4x + x2 = -1.12

The x term is -0.4x.  Take half its coefficient (-0.2).
Square it (0.04) and add it to both sides.

Add '0.04' to each side of the equation.
-0.4x + 0.04 + x2 = -1.12 + 0.04

Reorder the terms:
0.04 + -0.4x + x2 = -1.12 + 0.04

Combine like terms: -1.12 + 0.04 = -1.08
0.04 + -0.4x + x2 = -1.08

Factor a perfect square on the left side:
(x + -0.2)(x + -0.2) = -1.08

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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